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Asked: August 16, 20222022-08-16T15:04:37+00:00 2022-08-16T15:04:37+00:00In: Physics

When a constant force acts on an object with a mass of 8 kg for a duration of 3 s, it increases the object’s velocity from 4 ms-1 to 6 ms-1. What is the magnitude of the applied force?

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जब कोई स्थिर बल 3 s तक 8 kg द्रव्यमान की एक वस्तु पर कार्य करता है तो यह वस्तु के वेग को 4 ms-1 से 6 ms-1 तक बढ़ा देता है। लागू बल का परिमाण क्या है?
  1. 5.33 N
  2. 4.33 N
  3. 6.33 N
  4. 3.33 N
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    1. Best Answer
      Exampix Verified
      2022-08-16T15:07:51+00:00Added an answer on August 16, 2022 at 3:07 pm

      अवधारणा:

      • गति का समीकरण: किसी गतिशील वस्तु पर कार्य करनेवाले बल पर विचार किए बिना किसी गतिशील वस्तु के अंतिम वेग, विस्थापन, समय आदि को खोजने के लिए प्रयुक्त गणितीय समीकरणों को गति के समीकरण कहा जाता है।
      • ये समीकरण केवल तभी मान्य होते हैं जब निकाय का त्वरण स्थिर होता है और वे एक सीधी रेखा पर चलते हैं।

      गति के तीन समीकरण होते हैं:

      बल: यह किसी वस्तु पर लगाया जाने वाला एक प्रकार का धक्का या खिंचाव होता है जो इसे एक निश्चित दर पर त्वरित करता है।
      अर्थात्, बल एक निकाय में त्वरण उत्पन्न करता है।
      ∴ F = m × a

      जहाँ

      V = अंतिम वेग

      u = प्रारंभिक वेग

      s = गति के तहत निकाय द्वारा तय की गई दूरी

      a = गति के तहत निकाय का एक त्वरण

      t = गति के तहत निकाय द्वारा लिया गया समय

      गणना:

      दिया है कि

      वस्तु का द्रव्यमान = 8 kg

      वह समय जिसमें वस्तु पर बल कार्य करता है (t) = 3s

      वस्तु का प्रारंभिक वेग (u) = 4 m/s

      वस्तु का अंतिम वेग (v) = 6 m/s

      वस्तु पर लगाया गया बल = F

      वस्तु का त्वरण v = u +at

      6 = (4) +(a) (3)

      = 2/3

      अब न्यूटन के दूसरे नियम से, हमें मिलता है F = ma

      F = (8) (2/3) ⇒ 5.33

      लागू बल का परिमाण 5.33N है।


      CONCEPT:

      • Equation of motion: The mathematical equations used to find the final velocity, displacements, time, etc of a moving object without considering force acting on it are called equations of motion.
      • These equations are only valid when the acceleration of the body is constant and they move on a straight line.

      There are three equations of motion:

      Force: It is a kind of push or pulls applied to an object which causes it to accelerate at a certain rate
      i.e., Force produces acceleration in a body.
      ∴ F = m × a

      Where,

      V = final velocity,

      u = initial velocity,

      s = distance travelled by the body under motion,

      a = acceleration of body under motion,

      t = time taken by the body under motion.

      Calculation:​

      Given that,

      Mass of the object = 8kg.

      Time in which force acting on the body (t) = 3s

      initial Velocity of the object (u) = 4m/s

      Final Velocity of the object (v) = 6m/s

      Force applied on the object = F

      Acceleration of the object v = u +at.

      6 = (4) +(a) (3).

      = 2/3.

      Now from newton second law, we get F = ma

      F = (8) (2/3) ⇒ 5.33

      The magnitude of the applied force is 5.33N.

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