एक गेंद को 80 m की ऊंचाई से गिराया जाता है। तो चौथे सेकंड में इसके द्वारा तय की गई दूरी ________ होगी।
(g = 10 m/s2 लें)
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The distance travelled by a body in nth second is given by:
Sn = u + a/2 (2n – 1)
Where u is the initial velocity of the body, a is acceleration, and n is nth second.
The ball is dropped from 80 m height, so initial velocity (u) = 0 m/s
Acceleration is due to gravity (a) = 10 m/s2
and n = 4
For nth second, Sn = u + a/2 (2n – 1)
Distance travelled in 4th second (S4 ) = 0 + 10/2 (2 × 4 – 1) = 35 m